Adam takes a bus on a school field trip. The bus route splits into five legs listed in the table. Find the average velocity for each leg of the trip. Then arrange the legs of the trip from highest velocity to lowest.

 A) when D = 18 Km = 18000 m

and t = 9 min = 9*60 =540 s

So V = 18000m/ 540 S

      = 33 m/S

B) when D = 25 Km = 25000 m

and t = 15 min = 15 * 60 = 900 S

So V = 25000m / 900S

     = 27.8 m/s

C) when D = 24 Km = 24000 m

and t = 8 min = 8 * 60 = 480 s

So V = 24000m / 480s

     = 50 m/s

D) when D = 48 Km = 48000 m

and t = 12 min = 12 * 60 = 720 s

So V = 48000 m / 720s

       =66.7 m/s

E) when D = 15 km = 15000m

and t = 7 min = 7 * 60 = 420 s

So V = 15000m / 420s

      = 35.7 m/s

O

D

C

E

A

B

That's the answer from highest to lowest

Explanation:

when it gains or loses electrons

i already answered it by 34/s