NEED ASAP Look at the pic above and tell me the velocity, distance and time. Thanks!

Abody of weight 60 kg is standing in a lift the lift going upward with a uniform velocity of 4.9 metre per second slows down and stops in two seconds then apparent weight of the body during the slow down process is

I'm kinda lost ! 1. when marilyn takes her pet dog for a walk, the dog walks at a veryconsistent pace of 0.55 m/s. draw a position-time graph to representmarilyn's dog walking the 19.8 m distance from the front of her house tothe nearest fire hydrant.2. both car a and car bleave school when a stopwatch reads zero. car atravels at a constant 75 km/h, and car b travels at a constant 85 km/h. a) draw a position-time graph showing the motion of both cars. howfar are the two cars from school when the stopwatch reads 2 hrs? calculate the distances and show them on your graph. b) both cars passed a gas station 120 km from the school. when dideach car pass the gas station? calculate the times and show themon your graph.3. the figure below shows the position-time graph showing a shopper'smovement up and down the aisle at a store. a) write a story describing the shopper's movements at the store. b) when does the shopper have a position of 6 m? c) how much time passes between when the shopper enters the aisleand when he gets to a position of 12 m? what is the shopper's averagevelocity between 37 s and 46 s?

Brades exam guidelines exam instructions billing & payments & support question 6 of 20 : select the best answer for the question use this illustration to answer the question below. forms & resources al programs 9 ww linics 6. in the circuit shown in the figure above, suppose that the value of r, is 100k, and the value of r2 is 470 kq. at which of the following locations in the circuit would you measure the highest voltage with your meter? rvices 999999 a. between points b and c b. between points a and b c. between points b and e d. between points a and c eredu mark for review (will be highlighted on the review page) mend < < previous question next question