A rocket is launched at an angle of = 49° above the horizontal with an initial speed vi = 54 m/s, as shown below. It moves for 25 s along its initial line of motion wth an acceleration of 24.4 m/s2. At this time, its engines fail and the rocket proceeds to move as a free body.

yo yo yo its papaguy in the house lol

okay, ima .

um it shows links to uh so kinda microsoft website is that were ima go or no? ?

the minimum constant speed at which she can catch the train is 2.7 m/s

given:

acceleration = 0.6

time = 4.5 s

to find:

velocity = ?

formula used:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

solution:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

v = 0 + (0.6 × 4.5)

v = 2.7 m/s

the minimum constant speed at which she can catch the train is 2.7 m/s