A 700-kg car, driving at 29 m/s, hits a brick wall and rebounds with a speed of 4.5 m/s. If the car was in contact with the wall for 0.30 s, what force did the wall exert on the car during the collision?

Explanation:

Step one:

given data

mass=700kg

initial velocity u=29m/s

final velocity=4.5m/s

time t= 0.3second.

Step two:

The expression for the momentum is given as

FΔt=mΔv

make F subject of the formula

F=mΔv/Δt

Substitute our given data we have

F=700(29-4.5)/0.3

F=700*24.5/0.3

F=17150/0.3

F=57166.6N

the force is 57166.6N

c) up is the direction the magnetic force is acting on the charge.

d) physical means can be used to separate the components of air.