Calculate the acceleration of a bus whose speed changes from 16 m/s to 7 m/s over a period of 5 seconds.

W= fd
where f is an applied force and d is the distance over which it is applied. when a parachuting skydiver is at constant velocity, he is experiencing "terminal velocity", the point at which his acceleration down is canceled out by air resistance. that means that the resisting force of the air is equal to his weight, but in the opposite direction. with this, we can solve for the work done by the force.
w = fd
w = (92.0)(9.81 m/s^2) (325)
w= 2.93 x 10^5 j
the value for work in this case is positive because it is pushing up on the skydiver, who has a downward force of gravity.
therefore the answer is 2.93 x 10^5 j

Answerigneous bedrock of the oceanic crust;

The inference is supported by evidence in the graph is this is an exothermic reaction where the total release of energy equals a + c.

Fb is the magnetic force  q is the chargev is the velocity of the charge  b is the magnetic field  the equation is: f=|q|vbsin0