If the torque required to loosen a nut on a wheel has a magnitude of 40.0 N·m and the force exerted by a mechanic is 133 N, how far from the nut must the mechanic apply the force? Question 7 options:

1.) 0.15 m
2.) 0.6 m
3.) 0.3 m
4.) 1.2 m

3.) 0.3 m

Explanation:

Given parameters:

Torque  = 40Nm

Force = 133N

Unknown:

Distance from the nut that the mechanic must apply the force  = ?

Solution:

Torque is the force that causes an object to rotate on its axis;

  Torque  = force x distance

   Distance  =  = 0.3m

find the surface area of the sphere to the nearest square unit. use a calculator.

a. 254 in.2

b. 64 in.2

c. 127 in.2

d. 1,018 in.2

initial speed when it is dropped is 150 ft/s

now at the same moment the acceleration due to gravity is perpendicular to its velocity

so as we know that

now we have centripetal acceleration a = 32 ft/s^2 as its perpendicular to velocity

while tangential acceleration at the same moment will be zero

so

now radius of curvature is given as

so the radius of curvature just after it is dropped is 703.125 ft