A number minus four times a second number is at least –4. Three times the first number, then added to the second number, is more than –3. If x represents the first number and y represents the second number, which system of inequalities best represents the problem situation? 2x−4y≥−4 3x+2y>−3 2 x minus 4 y is greater than or equal to negative 4, , 3 x plus 2 y is greater than negative 3, , , x−4y≥−4 3x+y>−3 x minus 4 y is greater than or equal to negative 4, , 3 x plus y is greater than negative 3, , , 2x−4y<−4 3x+y>−3 2x−4y<−4, , 3 x plus y is greater than negative 3, , , x−4y≤−4 3x+y>−3

x - 4y ≥ -4

3x + y ≥ - 3

Explanation:

The first condition says that A number minus four times a second number is at least –4. So, taking x as first number and y as second number, we get:

x - 4y ≥ -4

Similarly, the other condition says that Three times the first number, then added to the second number, is more than –3. This will be represented as:

3x + y ≥ - 3

So, the system of inequalities that best represents the problem situation is:

x - 4y ≥ -4

3x + y ≥ - 3

because it says use -2,0,and 2 for x, we can plug those numbers into the equation. y/4=3/4(-2)+2   y/4= -1 1/2 +2 now to get x by itself, we can multiply each side by 4. y=-6+8 which equals y=2 when x=-2. now you can do the same thing with 0 and 2 as x. you get y=8 when x=0 and y=14 when x=2.

x   |   y

-2 |   2

0   |   8

2   |   14

seeing the graph would