a 90 gram object moves around a circle whose diameter is 2.56 m at a constant speed off 16 m/s. what is the object acceleration? how much time will take to complete the around?

and t = 0.5 s

Explanation:

Given that,

Mass of the object, m = 90 gram = 0.09 kg

Diameter of the circle, d = 2.56 m

Radius, r = 1.28 m

Speed, v = 16 m/s

We need to find the object acceleration. On the circular path, acceleration is given by :

So, the object's acceleration is .

Let t is time it will take to complete the around. Speed is given by :

So, time to cover one complete round is 0.5 s.

initial speed when it is dropped is 150 ft/s

now at the same moment the acceleration due to gravity is perpendicular to its velocity

so as we know that

now we have centripetal acceleration a = 32 ft/s^2 as its perpendicular to velocity

while tangential acceleration at the same moment will be zero

so

now radius of curvature is given as

so the radius of curvature just after it is dropped is 703.125 ft