A person slides a box down a ramp. The box starts from rest 2m above the lowest point. The ramp is frictionless. Once the box reaches the bottom there is friction. For every 1m the box travels on the flat part increases by 100 J. Where does the box stop? The box has mass of 5 kg.

.98m

Explanation:

Vf=Vi+2at

(V F)^2+2 ( change in distance )

X f= i ( change in V & T )

EK=1/2Mv^2,EG=mgh

explanation:

newton's third law, for every action there is an equal and opposite reaction.

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