The motor is lifting the 6 kg box at a constant velocity. How much work is done on the box to lift it 2 m? (Assume no resistance from the pulley.)

117.6 J

Explanation:

We use the formula for work as force times the distance. The force applied to lift the box at constant speed must equal the weight of the box:

F = m * g = 6 * 9.8 N = 58.8 N

Then we multiply this times the distance the box is moved:

Work = F * d = 58.8 * 2  J = 117.6 J

when it gains or loses electrons

note: the given question is incomplete.

complete question is given below.

which is an example of kinetic energy?

a. the energy stored in ethanol  

b. a hockey puck sliding across the ice  

c. a compressed spring  

d. a ball sitting at the top of a ramp

solution: the kinetic energy is the energy posses by the virtue of the motion of the object.

in the given options, a, c and d are the example of potential energy because it is the energy posses by the virtue of the rest of the object. but option b has the kinetic energy as the object is in motion.

hence, a hockey puck sliding across the ice   is the apex example of kinetic energy.

so, the option (b) a hockey puck sliding across the ice   is the correct option.