Sarah weighs 392 N. She pushes a 56 kg rock with a force of 65 N. What force does the rock exert on Sarah?

The force the rock exerts on Sarah =#is 65 N

Explanation:

The given parameters are;

Sarah's weight = 392 N

The force with which Sarah pushes the rock = 65 N

The mass of the rock = 56 kg

The weight of the rock = The mass of the rock × Acceleration due to gravity

∴ The weight of the rock = 56 kg ×9.81 m/s² = 549.36 N

Given that the force Sarah applies to push the rock = 65 N, then by Newton's third law of motion which states that action and reaction are equal and opposite, the force that the rock exert on Sarah is equal an opposite to the force Sarah is applying

Therefore, the force the rock exerts on Sarah = 65 N (in the opposite direction).

because it says use -2,0,and 2 for x, we can plug those numbers into the equation. y/4=3/4(-2)+2   y/4= -1 1/2 +2 now to get x by itself, we can multiply each side by 4. y=-6+8 which equals y=2 when x=-2. now you can do the same thing with 0 and 2 as x. you get y=8 when x=0 and y=14 when x=2.

x   |   y

-2 |   2

0   |   8

2   |   14

the answer is a. hope this .