lasers 1 and 2 emit light of the same color, and the electric field in the beam of laser 1 is twice as strong as the e-field of laser 2. how do the intensities of the two lasers compare?

The intensity of laser 2 is 4 times of the intensity of laser 1.

Explanation:

The intensity in terms of electric field is given by :

E is electric field

It means,

In this problem, lasers 1 and 2 emit light of the same color, and the electric field in the beam of laser 1 is twice as strong as the e-field of laser 2.

Let E is electric field in the beam of laser 1 and E' is the electric field in the beam of laser 2. So,

We have,

E'=2E

So,

So, the intensity of laser 2 is 4 times of the intensity of laser 1.

pe = weightxheight = 2000x1000=2,000,000joules

need to see circuit to get time constant