4. How much energy must be absorbed by water with a mass of 0.5 kg in order to raise the temperature from 30°C to 65°C? Note: Water has a specific heat of 4.190 J kg °C.

Q = 73325 J or 73.325 KJ

Explanation:

Given the following data;

Specific heat capacity of water = 4190

Mass = 0.5kg

dt = 65 - 30 = 35°C

Heat capacity is given by the formula;

Q = mcdt

Where,

Q represents the heat capacity.

m represents the mass of an object.

c represents the specific heat capacity of water.

dt represents the change in temperature.

Substituting into the equation, we have:

Q = 0.5 * 4190 * 35

Q = 73325 Joules.

question1

1,000 tons

question2

3: 8

question 3

store d

step-by-step explanation:

1/0.14nm = 10^10/1.4 a lot