A squirrel on a limb near the top of a tree loses its grip on a nut, so that the nut slips away horizontally at a speed of 1.5m/s. If the nut lands at a horizontal distance of 7.2m, how high above the ground is the squirrel?

The height of the squirrel  

Explanation:

From the question we are told that  

    The horizontally speed is

    The horizontal  distance

Generally the the time taken is mathematically represented

=>  

=>  

Generally from kinematic equation we have that

Here u  is the initial velocity of nut in the vertical and the value is 0 m/s

=>  

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