How much voltage is present in a circuit that carries 0.02 A with a resistance of 400 Ω?

8V

Explanation:

Given parameters:

Current = 0.02A

Resistance  = 400Ω

Unknown:

Voltage in the circuit = ?

Solution:

The voltage in a circuit is the driving force of the system.

According to ohms law;

    V  = IR

V is the voltage

I is the current

R is the resistance

 So;

  input the parameters and solve;

           V = 0.02 x 400  = 8V

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