How much voltage is present in a circuit that carries 0.012 A with a resistance of 300 Ω?

3.6V

Explanation:

Given parameters:

Current  = 0.012A

Resistance  = 300Ω

Unknown:

Voltage  = ?

Solution:

According to ohm's law, voltage in a circuit is expressed mathematically as shown below:

   Voltage = Current x Resistance

 Insert the given parameters and solve;

 Voltage  = 0.012 x 300 = 3.6V

a

explanation:

no diagram was provided, but i'm guessing it's the one i've attached to my answer.

here, a mechanical force turns the rod.   this generates an electric current in the coil, which powers the bulb.

i believe the answer is a hope it and is correct