4) The power supplies in 1206 Mudd feature an internal protection mechanism that limits the output current to 1 ampere (oh no, not that again). Ideally, the protection circuit engages instantaneously when an over-current fault is detected, then disengages instantaneously once the fault condition is removed. While in the current limited state, the supply acts like an ideal current source. Now suppose you set the supply to 5 volts then connect a 1H inductor (huge!) to it.(a) how long will it take for the supply to go into current-limit

0.2 seconds

Explanation:

Given data  :

Output Data = 1 ampere

supply voltage = 5 volts

inductor = 1 H

A) calculate how long before the supply goes into current limit

we apply this relationship used for determining output voltage

V = ------- ( 1 )

L = 1 H

di = 1 ampere

dt = ?

V = 5 volts

considering equation 1 above

dt ( time before supply goes into current limit ) =  1 / 5 = 0.2 seconds

which statement about this sum is true? −245+2.7

the minimum constant speed at which she can catch the train is 2.7 m/s

given:

acceleration = 0.6

time = 4.5 s

to find:

velocity = ?

formula used:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

solution:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

v = 0 + (0.6 × 4.5)

v = 2.7 m/s

the minimum constant speed at which she can catch the train is 2.7 m/s