A 6000 kg rocket is launched vertically from the ground. If the exhaust speed is 1000 m/s, how much gas must be ejected each second if the thrust is to equal the magnitude of the gravitational force on the rocket

60kg/sec

Explanation:

From the question, the mass is given as:

Mass, m = 6000kg

The formula for thrust us calculated as:

F = u × dt/dm

We then equate thrust = weight. This will be:

1000 × dt/dm =mg

1000 × dt/dm = 6000 × 10

1000 × dt/dm = 60000

dt/dm = 60,000/1,000

dt/dm = 60kg

Therefore, the gas ejected per second will be 60 kg/s

the order for strong to weak forces such as

strong nuclear force → electromegnetic force → weak nuclear force → gravitational force

the fundamental forces are those forces that act between to objects or element to make interactions. there are four types of fundamental forces such as strong and weak nuclear forces (due to protons and electrons), electromagnetic force (due to the motion of electrons) and gravitational force (due to orbital movement of the planet). if these forces are arranged on the basis of their maximum strength then the order is

strong nuclear force → electromegnetic force → weak nuclear force → gravitational force