Problem 8.6 2 of 10 Review Each piston has a radius of 45 mm and the cylinder has a wall thickness of 2 mm . Force P acts on plungers moving toward each other in a cylinder of radius 45 millimeters. Part A Determine the maximum force P that can be exerted on each of the two pistons so that the circumferential stress in the cylinder does not exceed 8 MPa . Express your answer to three significant figures and include appropriate units.

P = 4.5 x 10³ N = 4.5 KN

Explanation:

The circumferential stress will be the stress acting upon the circumference thickness area of the cylinder due to the force P. It can be calculated by following formula:

Cs = P/2πrt

where,

Cs = Circumferential Stress = 8 MPa = 8 x 10⁶ Pa

P = Force = ?

r = radius of cylinder = 45 mm = 0.045 m

t = thickness of cylinder wall = 2 mm = 0.002 m

Therefore,

8 x 10⁶ Pa = P/(2)(π)(0.045 m)(0.002 m)

(8 x 10⁶ Pa)(5.65 x 10⁻⁴ m²) = P

P = 4.5 x 10³ N = 4.5 KN

1.195000

explanation:

total mass=0.0117+0.0137+0.0881+0.0111

total mass= 0.01172kg

total velocity = 0.283-0.743+0.871-0.799+0.155+0.637+0.301=0.102

momentum=mv=0.1172*0.102=1.195000//