Ex 11 ) A salmon jumps vertically out of the water at an initial velocity of 6 m/s. What is the height it will jump?

1.84m

Explanation:

Given parameters:

Initial velocity  = 6m/s

Unknown:

height of jump  = ?

Solution:

To solve this problem, we have to apply the right motion equation:

        V²  = U²  - 2gH

V is the final velocity

U is the initial velocity

g is the acceleration due to gravity  = 9.8m/s²

H is the height

   Final velocity is 0

  Solve;

           0² = 6² - 2x9.8xH

           -36  = -19.6H

               H = 1.84m

in simple terms, the principle states that the buoyancy force on an object is equal to the weight of the fluid displaced by the object, or the density of the fluid multiplied by the submerged volume times the gravitational acceleration, g. this is also known as upthrust.