A glass ball of radius 2 cm is placed in a vertical cylindrical vessel of radius 20 cm filled with water and rotating at an angular velocity Ω about the axis of symmetry of the cylinder. After equilibration, the vessel, the water in the vessel, and the ball rotate at the same angular velocity 10 rad/s, the ball being on the bottom at the vertical wall of the rotating vessel. Find the force with which the ball acts on the vessel. Glass density is 2.5 g/cm^3, water density is 1 g/cm^3. Freefall acceleration is 10 m/s^2.

answer plz refer to this one

air exerts forces on falling objects near earth’s surface.

explanation:

the term 'free falls' refer to object that are falling towards the earth, in a situation in which gravity is the only force acting on the object.

for an object in free fall, the acceleration is constant (g, the gravitational acceleration), and so the velocity of the object constantly increases.

for objects near earth's surface, there is always another force acting on the object: the resistance due to the air. this force is opposed to the direction of fall of the object, and it is proportional to the velocity of the object, so as the object falls down, this force increases up to a point when it balances the force of gravity, and the object continues its motion at constant velocity (called terminal velocity). since in this case gravity is not the only force acting on the object, we are not in a situation of free fall.