Two men pull a 31-kg box with forces 9.7 N and 7.6N in the directions shown below. Find the resultant acceleration of the box and the direction in which the box moves.

Explanation:

Given that,

Mass of the box, m = 31 kg

The two forces are shown in the attached figure. They are acting in opposite direction.

Net force, F = 9.7 - 7.6 = 2.1 N

The formula for net force is given by :

F = ma

a is resultant acceleration

So, the resultant acceleration is .

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W= fd
where f is an applied force and d is the distance over which it is applied. when a parachuting skydiver is at constant velocity, he is experiencing "terminal velocity", the point at which his acceleration down is canceled out by air resistance. that means that the resisting force of the air is equal to his weight, but in the opposite direction. with this, we can solve for the work done by the force.
w = fd
w = (92.0)(9.81 m/s^2) (325)
w= 2.93 x 10^5 j
the value for work in this case is positive because it is pushing up on the skydiver, who has a downward force of gravity.
therefore the answer is 2.93 x 10^5 j