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a = - 1 [m/s²]

Explanation:

To solve this problem we must use the following equation of kinematics.

where:

Vf = final velocity = 0 (velocity at 10 seconds)

Vo = initial velocity = 4 [m/s]

a = desacceleration [m/s²]

t = time = 4 [s]

From the graph, we can deduce that between the second 10 and the second 6 there are (10-6) = 4 seconds difference.

In the second 6, the velocity is 4 [m/s]

0 = 4 + (a*4)

4*a = -4

a = - 1 [m/s²]