The current in secondary of coil of a transformer is 1 A and that in primary is 0.5 A. If 200V is available in the secondary what is the voltage in the primary?

400 V

Explanation:

The following data were obtained from the question:

Current in secondary coil (Iₛ) = 1 A

Current in primary coil (Iₚ) = 0.5 A

Emf in secondary coil (Eₛ) = 200 V

Emf in primary coil (Eₚ) =.?

The voltage (i.e emf) in the primary coil can be obtained as illustrated below:

Eₛ / Eₚ = Iₚ / Iₛ

200/Eₚ = 0.5/1

Cross multiply

Eₚ × 0.5 = 200 × 1

Eₚ × 0.5 = 200

Divide both side by 0.5

Eₚ = 200/0.5

Eₚ = 400 V

Therefore, the voltage in the primary coil is 400 V

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explanation:

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