Acceleration due to gravity (ag) = 9.8 m/s2. An object is dropped from a bridge. How fast will the object be falling in 6.3 seconds?

V = 61.74m/s

Explanation:

Given the following data;

Acceleration due to gravity = 9.8m/s²

Time, t = 6.3 secs

Since it's a free fall, initial velocity = 0

Thus, to find the final velocity, we would use the first equation of motion;

Substituting into the equation, we have;

V = 61.74m/s

Therefore, the final velocity is 61.74m/s

e

explanation:

there is no change in the electric potential energy as it is in rest on both conditions.