9. A 0.25-kg mass is attached to a string and swung in a vertical circle whose radius is 0.75 m. At the bottom of the circle, the mass is observed to have a speed of 10 m/s. What is the magnitude of the tension in the string at that point

T =  33.34 N

Explanation:

Given that,

Mass attached to the spring, m = 0.25 kg

Radius of the vertical circle, r = 0.75 m

Speed of the mass, v = 10 m/s

We need to find the magnitude of the tension in the string at that point. We know that the tension in the string is equal to the centripetal force acting on it. It can be given by

So, the tension in the string is 33.34 N.

. west

the chart show the masses and velocities of two colliding objects that stick together after a collision.

according to the law of conservation of momentum, the momentum of the object after the collision is  

answer

1,500

kg • m/s.