What is the angle between a wire carrying an 8.00-A current and the 1.20-T field it is in if 50.0 cm of the wire experiences a magnetic force of 2.40 N? (b) What is the force on the wire if it is rotated to make an angle of 90 ∘ 90∘ with the field?

(a) the angle between the wire and field is 30⁰

(b) the force is 4.8 N

Explanation:

Given;

current in the wire, I = 8 A

magnetic field, B = 1.2 T

length of the wire, L = 50.0 cm = 0.5 m

magnetic force, F = 2.4 N

The magnetic force on the wire is given by;

F = BILsinθ

where;

θ is the angle between the wire and field

sinθ = F / BIL

sinθ = 2.4 / (1.2 x 8 x 0.5)

sinθ = 0.5

θ = sin ⁻¹ (0.5)

θ = 30⁰

(b) the force on the wire if it is rotated to make an angle of 90⁰

F = BIL(sin90⁰)

F = BIL(1)

F = BIL

F = 1.2 x 8 x 0.5

F = 4.8 N