How much time is required for an airplane to reach its takeoff speed of 77m/a if it starts from rest and its average acceleration is 8.2m/s^2?

The time required is t = 9.39 [s]

Explanation:

To solve this problem we must use the following equation of kinematics.

where:

Vf = final velocity = 77 [m/s]

Vo = initial velocity = 0

a = acceleration = 8.2 [m/s²]

t = time [s]

The initial speed is zero, since the airplane begins its movement from rest. The initial speed is zero, since the aircraft begins its movement from rest. Another important fact is that the sign of acceleration is positive since the plane is accelerating, that is, its speed is increasing.

Now replacing:

77 = 0 + (8.2*t)

t = 9.39 [s]

part 1: which substance has a higher solubility?

a

smallest amount left undissolved atall temps in table shown most has dissolved high sol'by