A falling rock is viewed to pass by a window that has a height of 2.2 m in 0.40 s a. Find the V of the rock as it reaches the bottom of the window
b. What height above the window was the rock dropped from, initially?

the results is a decrease in air temperature with an increase of altitude.

explanation:

probably not if net force is zero

electrical potential energy =0.072 j

explanation:

electrical potential energy is given by

u= q δv

q= charge=6 c

δv= potential difference and is given by

δv= e d

e= electric field

d= distance=5 mm=0.005 m

δv=2.4 (0.005)=0.012 v

now electric potential energy= u= q δv

u=6 (0.012)

u=0.072 j

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