Physics, 26.10.2020 17:20 shelbylynn17

) Determine the pressure difference (in bar and in psi) between the inside and outside of an ultra-small air droplet near the surface of water given that the droplet diameter is

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Answer from: teionamwhite2262

Complete Question

The complete question is shown on the first uploaded image

$P = 292 \ bar$

$P_{psi} = 4235.17 \ psi$

$P = 2.92 \ bar$

$P_{psi} = 42.3517 \ psi$

$P = 2.92*10^{-5} \ bar$

$P_{psi} = 0.0423517 \ psi$

Explanation:

From the question we are told that

$1 \ bar = 10^{5} Pa = 14.504 \ psi$

$\sigma_s = 0.073 \ N/m \ at \ 20^oC$

Generally the pressure difference is mathematically represented as

$P = \frac{2 \sigma_s }{r}$

Considering question a

Here the diameter is $d = 10 nm = 10*10^{-9} \ m$

Generally the radius is mathematically represented as

$r = \frac{d}{2} = \frac{10*10^{-9}}{2} = 5*10^{-9} \ m$

$P = \frac{2 * 0.073 }{5*10^{-9}} \ Pa$

=> $P = 292 *10^{5}\ Pa$

Converting to bar

$P_{bar} = \frac{292 *10^{5}}{1*10^{5}}$

$P = 292 \ bar$

Converting to psi

$P_{psi} = \frac{ 292 *10^{5}}{14.504}$

$P_{psi} = 4235.17 \ psi$

Considering question b

Here the diameter is $d = 1\mu m = 1*10^{-6} \ m$

Generally the radius is mathematically represented as

$r = \frac{d}{2} = \frac{1*10^{-6}}{2} = 0.5*10^{-6} \ m$

$P = \frac{2 * 0.073 }{ 0.5*10^{-6}} \ Pa$

=> $P = 292 *10^{3}\ Pa$

Converting to bar

$P_{bar} = \frac{292 *10^{3}}{1*10^{5}}$

$P = 2.92 \ bar$

Converting to psi

$P_{psi} = \frac{ 292 *10^{3}}{14.504}$

$P_{psi} = 42.3517 \ psi$

Considering question c

Here the diameter is $d = 1mm = 1*10^{-3} \ m$

Generally the radius is mathematically represented as

$r = \frac{d}{2} = \frac{1*10^{-3}}{2} = 0.5*10^{-3} \ m$

$P = \frac{2 * 0.073 }{ 0.5*10^{-3}} \ Pa$

=> $P = 292 \ Pa$

Converting to bar

$P_{bar} = \frac{292 }{1*10^{5}}$

$P = 2.92*10^{-5} \ bar$

Converting to psi

$P_{psi} = \frac{ 292 }{14.504}$

$P_{psi} = 0.0423517 \ psi$

) Determine the pressure difference (in bar and in psi) between the inside and outside of an ultra-s

Answer from: Quest

russian is not my first language, so i'm afraid i can't write out an answer in russian, but hopefully you can find a way to do so. here's my best translation of the problem: you're given a plot of a particle's position in one-dimensional space over time, and you're asked to find either the total distance traveled by the particle after 6 seconds had elapsed, or the total displacement of the particle after 6 seconds.

if you want the total distance traveled, you would first need to determine the particle's velocity as a function of time, then integrate that over the 6-second interval. we know the position function is quadratic with roots at 0 and 6, so we have

$x(t)=ax(x-6)$