What will be the volumetric flow through the pipe if the mean fluid velocity is 10 ft/sec and the pipe has an outer diameter of 4.95 inches and a thickness of 0.25 inch

The volumetric flow through the pipe is 1.21 ft³/s

Explanation:

Given;

fluid mean velocity, v = 10 ft/s

outer diameter of the pipe, d₀ = 4.95 inches = 0.4125 ft

thickness of the pipe, x = 0.25 inches = 0.0208 ft

the inner diameter of the pipe, d₁ = d₀ - x = 0.4125 ft - 0.0208 ft = 0.3917 ft

the area of the pipe =

The volumetric flow rate of the pipe is given by;

Q = Av

Q = (0.121 ft²) (10 ft/s)

Q = 1.21 ft³/s

Therefore, the volumetric flow through the pipe is 1.21 ft³/s

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