A toy projectile is fired from the ground vertically upward with an initial velocity of +29 meters per second. The projectile arrives at its maximum altitude in 3.0 seconds. [Neglect air resistance.] 1. The greatest height the projectile reaches is approximately

The greatest height the toy projectile reaches =

Projectile motion is an example  a plane motion in two dimensions.

The equations for projectile motion are derived from the equations of motions applied in x and y directions.

The maximum height of the flight is achieved at the point where the velocity in  +y  direction becomes Zero and just after that the projectile keeps accelerating.

The maximum height of the projectile is given by equation (1)

Initial velocity = 29 m/s

Angle of projection = 90 ° (vertically upwards)

Putting in equation (1)

For more information please refer to  the link below

link

Explanation:

According to projectile, the maximum height reached by the toy is expressed as:

H = u²sin²Ф/2g

u is the initial velocity = 29m/s

Ф = 90° (projected vertically upward)

g is the acceleration die to gravity = 9.81m/s²

Substitute into the formula:

H = u²sin²Ф/2g

H = 29²sin²90/2(9.81)

H = 841(1)/19.62

H = 42.86m

Hence the greatest height the projectile reaches is approximately 43m

does anyone know or what?