A fish swimming in a horizontal plane has velocity v→i=(4.00i^+1.00j^) m/s at a point in the ocean where the position relative to a certain rock is r→i=(10.0i^−4.00j^) m . After the fish swims with constant acceleration for 20.0 s , its velocity is

b) returns freshwater to the earth.

c) returns freshwater to the earth.c) occurs after condensation.

d) returns freshwater to the earth.c) occurs after condensation.d) roughly equal to the amount of evaporation.

happy to

pls mark as brainliest.

wind moving at higher speeds will transfer more energy to the water, resulting in stronger waves.

i don't know that i agree with that but what's the question ?

initial speed when it is dropped is 150 ft/s

now at the same moment the acceleration due to gravity is perpendicular to its velocity

so as we know that

now we have centripetal acceleration a = 32 ft/s^2 as its perpendicular to velocity

while tangential acceleration at the same moment will be zero

so

now radius of curvature is given as

so the radius of curvature just after it is dropped is 703.125 ft