Physics, 26.10.2020 05:30 ruffnekswife

NEED HELP ASAP PLS (with work) A punt is kicked at an angle of 60 with a speed of 40 m/s, and lands at the same
height from which it was kicked.

How far away will the ball land?

What is the maximum height reached by the ball?

What is the hang time? Total

Answers: 2

Show answers

Answers

Answer from: MorgannJ

1) The ball will land approximately 141.4 m away from where it was kicked

2) The maximum height reached is approximately 61.22 m

3) The total hang time is approximately 7.07 seconds

Explanation:

First we list out the known parameters

The direction in which the punt is kicked, θ = 60°

The speed with which the punk is kicked, v₀ = 40 m/s

1) The distance away (the range, R) the ball will land is given by the equation;

$R = \dfrac{v_0^2 \times sin(2\cdot \theta)}{g}$

Where;

g = The acceleration due to gravity = 9.8 m/s²

Substituting the values, gives;

$R = \dfrac{40^2 \times sin(2\times60^{\circ })}{9.8} \approx 141.4 \ m$

The distance away the ball will land ≈ 141.4 m

2) The maximum height is given m=by the following equation for vertical motion;

(v₀ × sin(θ))² = 2 × g × $h_{max}$

Obtained from the equation of motion, v² = u² - 2×g×h where at maximum height;

v = 0 at maximum height, the ball stops upward motion

h = Height of motion = $h_{max}$ at maximum height

v, and u are the vertical component of the velocity, v₀

Substituting the values in the equation for the maximum height, gives;

(40 × sin(60))² = 2 × 9.8 × $h_{max}$

(40 × (√3)/2)² = 1200 = 19.6 × $h_{max}$

1200 = 19.6 × $h_{max}$

$h_{max}$ = 1200/19.6 ≈ 61.22 m

The maximum height reached ≈ 61.22 m

3) The time to maximum height is given by the following equation of motion;

v_y = v₀ × sin(θ) - g × t

v_y = 0 at maximum height

We therefore have;

v₀ × sin(θ) = g × t

t = v₀ × sin(θ)/g = 40 × sin(60°)/9.8 = (40 ×(√3)/2)/9.8 = 3.535 seconds

Given that the motion of the ball is symmetrical about the maximum height, we have;

The time from ground level to maximum height = The time from the maximum height back to the ground level

The total time hang time = The time from ground level to maximum height + The time from the maximum height back to the ground level

The total time hang time ≈ 3.535 + 3.535 ≈ 7.07 seconds.

The total time hang time ≈ 7.07 seconds.

Answer from: Quest

electrical power

Answer from: Quest

Yup no bull frogs here man

Other questions on the subject: Physics

Physics, 22.06.2019 00:30, eskarletche8

The plum pudding model of the atom state that ?

Answers: 2

continue

Physics, 22.06.2019 03:00, natasniebow

Which of the following harmful chemicals are found in tobacco smoke? a. carbon monoxide b. carbon dioxide c. nicotine b. carbon dioxide d. both a and c

Answers: 2

continue

Physics, 22.06.2019 05:00, bbygrl70

Aperson stands on a platform, initially at rest, that can rotate freely without friction. the moment of inertia of the person plus the platform is ip. the person holds a spinning bicycle wheel with its axis horizontal. the wheel has moment of inertia iw and angular velocity ωw. take the ωw direction counterclockwise when viewed from above. part a what will be the angular velocity ωp of the platform if the person moves the axis of the wheel so that it points vertically upward?

Answers: 1

continue

Physics, 22.06.2019 11:10, axxpjr12

Consider an insulating crystal, made up of layers of atoms. what form would you expect the temperature dependence of the phonon heat capacity to approach at extremely low temperatures if the interlayer coupling is i)very strong (rigid coupling), and ii) very weak. explain.

Answers: 3

continue

You know the right answer?

NEED HELP ASAP PLS (with work) A punt is kicked at an angle of 60 with a speed of 40 m/s, and lands...