A 45 kg wagon is being pulled with a rope that makes an angle of 380 with the horizontal. The applied force is 410 N and the coefficient of kinetic friction between the wagon and the ground is 0.18. b) What are the x and y components of the applied force?
c) What is the normal force acting on the wagon? Is this greater than or less than the wagon’s weight? What impact does this have on the kinetic friction force?
d) Find the acceleration of the wagon in the x direction.

b) What are the x and y components of the applied force? the X component is 45 kg the Y component is 410 N

What is the normal force acting on the wagon? Is this greater than or less than the wagon’s weight? (greater)  What impact does this have on the kinetic friction force?

Explanation:

i was thinking more like reflects green light, just not sure

the minimum constant speed at which she can catch the train is 2.7 m/s

given:

acceleration = 0.6

time = 4.5 s

to find:

velocity = ?

formula used:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

solution:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

v = 0 + (0.6 × 4.5)

v = 2.7 m/s

the minimum constant speed at which she can catch the train is 2.7 m/s