Where was runner A located at t = 0 s? Which runner was ahead at t = 48.0 s?
When runner A was at 0.0 m, where was runner B?
How far apart were runners A and B at t = 20.0 s?

the answer is f1 and d2 because if you put equal force on those two points the beam would balance trust me on this

force required to detach it is given by

charges are taken to be fundamental charge

now we have

so above is the minimum distance at which it will detach

1.195000

explanation:

total mass=0.0117+0.0137+0.0881+0.0111

total mass= 0.01172kg

total velocity = 0.283-0.743+0.871-0.799+0.155+0.637+0.301=0.102

momentum=mv=0.1172*0.102=1.195000//

b. false

explanation:

suppose a rock in free fall is dropped off a cliff. after falling for 5 seconds, its speed would not be 100 m/s.