A 43kg block rests on a surface with 61N of friction and is being pushed by a 23N force. What is the acceleration?

The acceleration of the block is -0.884 m/s²

Explanation:

Given;

mass of the block, m = 43 kg

frictional force, Fk = 61 N

applied force on object, F = 23 N

The net horizontal force on the body is given by;

∑Fx = F - Fk

∑Fx = 23 N - 61 N

∑Fx = -38 N

Apply Newton's second law of motion;

F = ma

a = F/m

a = -38 / 43

a = -0.884 m/s²

this is the deceleration of the block, because the applied the applied force is than the frictional force; which is preventing forward motion of the block.

Therefore, the acceleration of the block is -0.884 m/s²

answer; how far out of place which the object finished relative to the starting location;