A cannon is fired horizontally from the edge of a small cliff. The height of the cliff is 104.0 m. The cannon ball is fired with a perfectly horizontal velocity of 24.6 m/s and it took 2.3s to reach the ground. How far will the cannon ball fly horizontally before it strikes the ground?

h = 134.65 m

Explanation:

It is given that,

The height of the cliff is 104.0 m, h₀ = 104 m

Initial horizontal velocity of the ball, u = 24.6 m/s

It takes 2.3 s to reach the ground, t = 2.3 s

We need to find how far will the cannon ball fly horizontally before it strikes the ground. let it is h. Using second equation of motion as follows :

Here, a = -g

So,

So, the cannonball will cover a distance of 134.65 m before it strikes the ground.

initial speed when it is dropped is 150 ft/s

now at the same moment the acceleration due to gravity is perpendicular to its velocity

so as we know that

now we have centripetal acceleration a = 32 ft/s^2 as its perpendicular to velocity

while tangential acceleration at the same moment will be zero

so

now radius of curvature is given as

so the radius of curvature just after it is dropped is 703.125 ft