A dog walks 40. m west, then 10. m east and then 50. m south. What is the distance and displacement traveled?

The total distance traveled by the dog is 100 m and the displacement of the dog is 58.31 m.

The given parameters;

The displacement of the dog is the change in its initial position and the final position.

The resultant of the dogs position in x-direction: = 40 m - 10 m = 30 m

The resultant of the dogs position in y-direction: 50 m

The magnitude of the displacement;

R² = 30²  + 50²

R² = 3400

R = √3400

R = 58.3 m

The distance covered by the dog is the sum of all the positions of the dog.

Distance = 40 m + 10 m + 50 m

Distance = 100 m.

Thus, the total distance traveled by the dog is 100 m and the displacement of the dog is 58.31 m.

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find the surface area of the sphere to the nearest square unit. use a calculator.

a. 254 in.2

b. 64 in.2

c. 127 in.2

d. 1,018 in.2

the answer is c. the lower legs are levers, and the knees are fulcrums. the ankles hold the loads.