A jet airliner moving initially at 693 mph (with respect to the ground) to the east moves into a region where the wind is blowing at 798 mph in a direction 37◦ north of east. What is the new speed of the aircraft with respect to the ground? Answer in units of mph.

The new speed of the aircraft with respect to the ground is 1414.3 mph.

Explanation:

Given that,

Angle = 37°

Velocity of jet airliner = 693 mph

Velocity of wind = 798 mph

We know that,

The new velocity of the aircraft with respect to the ground

We need to calculate the new speed of the aircraft with respect to the ground

Using formula for velocity

Put the value into the formula

Hence, The new speed of the aircraft with respect to the ground is 1414.3 mph.

yup its correct its: c) b b

speed of light in vacuum is 300,000 km/s

speed of light in other mediums is given by the expression v = c/n, where c is the speed of light in vacuum and n is the refractive index of medium.

for the first medium v = 200,000 km/s

  so, refractive index of medium = 300000/200000 = 1.5

    1.5 refractive index is usually for glass. so first medium is glass.

for the second medium v = 250,00 km/s

so, refractive index of medium = 300000/250000 = 1.2

    1.2 refractive index is usually for water. so second medium is water.

for the third medium v = 0 km/s

so, refractive index of medium = 300000/0 = ∞

    ∞ refractive index is usually for opaque mediums. so third medium is opaque medium.