Physics, 21.10.2020 16:01 benwill0702
How much voltage (in terms of the power source voltage bV) will the capacitor have when it has started at zero volts potential difference, it is connected to the power supply and resistor and onehalf the characteristic time has passed (i. e. t= T(tau)/2)?
Answers: 2
is know as the time constant 
![V = V_b [1 - e^{- \frac{t}{\tau} }]](/tpl/images/0827/6789/1d224.png)
![V = V_b [1 - e^{- \frac{\frac{\tau}{2}}{\tau} }]](/tpl/images/0827/6789/2e5b5.png)
![V = V_b [1 - e^{- \frac{\tau}{2\tau} }]](/tpl/images/0827/6789/1975c.png)
![V = V_b [1 - e^{- \frac{1}{2} }]](/tpl/images/0827/6789/e7acd.png)
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How much voltage (in terms of the power source voltage bV) will the capacitor have when it has start...
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