A motorcycle is driven horizontally straight off a 22-m tall cliff with a speed of 65 m/s. How far from the base of the cliff will the motorcycle land?

137.8 m

Explanation:

The following data were obtained from the question:

Height (h) = 22 m

Initial velocity (u) = 65 m/s

Horizontal distance (s) =.?

Next, we shall determine the time taken for the motorcycle to get to the ground. This can be obtained as follow:

Height (h) = 22 m

Acceleration due to gravity (g) = 9.8 m/s²

Time (t) =?

h = ½gt²

22 = ½ × 9.8 × t²

22 = 4.9 × t²

Divide both side by 4.9

t² = 22/4.9

Take the square root of both side.

t = √(22/4.9)

t = 2.12 s

Finally, we shall determine the horizontal distance travelled by the motorcycle. This is illustrated below:

Initial velocity (u) = 65 m/s

Time (t) = 2.12 s

Horizontal distance (s) =.?

s = ut

s = 65 × 2.12

s = 137.8 m

Thus, the motorcycle will land at 137.8 m away from the cliff

the ima (higher than 1m) will be greater than the ima with the height of 1m.