a 100 foot cliff drops vertically to a lake if the angle of elevation from a swimmer to the top of the cliff is 54.6 how far is the swimmer from the clif

Explanation:

Please see attached photo for explanation.

In the attached photo, X is the distance of the swimmer from the cliff.

Thus, we can obtain the value of x by using Tan ratio as illustrated below:

θ = 54.6°

Opposite = 100 foot

Adjacent = x =.?

Tan θ = Opposite /Adjacent

Tan 54.6 = 100/x

Cross multiply

x × Tan 54.6 = 100

Divide both side by Tan 54.6

x = 100 / Tan 54.6

x = 71.07 foot

Therefore, the swimmer is 71.07 foot from the cliff.

W= fd
where f is an applied force and d is the distance over which it is applied. when a parachuting skydiver is at constant velocity, he is experiencing "terminal velocity", the point at which his acceleration down is canceled out by air resistance. that means that the resisting force of the air is equal to his weight, but in the opposite direction. with this, we can solve for the work done by the force.
w = fd
w = (92.0)(9.81 m/s^2) (325)
w= 2.93 x 10^5 j
the value for work in this case is positive because it is pushing up on the skydiver, who has a downward force of gravity.
therefore the answer is 2.93 x 10^5 j