The radius of Mars is 3.4 x 10^6m and the period of Mars's rotation is 24 hours. What is the radial accelerations (in m/s^2) of an object on the ground at its equator? A. 0.018m/s^2
B. 0.136m/s^2
C. 0.068m/s^2
D. 0.376m/s^2

Option A: 0.018m/s^2

Explanation:

Formula for radial acceleration is;

α_r = ω²r

Now, ω = 2π/T

We're given T = 24 hours. Converting to seconds is; T = 24 × 60 × 60 seconds

ω = 2π/(24 × 60 × 60)

We are given radius = 3.4 × 10^(6) m

Thus;

α_r = (2π/(24 × 60 × 60))² × 3.4 × 10^(6)

α_r = 0.018 m/s²

massxgravity x heght=weightxheight= pe

4900=490xh

h=10

the old price per ounce is c/4.

the new price per ounce is c/3.6.

the ratio of the old price to the new one is

(c/4)/(c/3.6) = (c/c)×(3.6/4) = 0.9 . . = 9/10 . . "nine tenths" in either form