A baseball pitcher makes a big mistake and throws the ball straight up. If it reaches a maximum height of 15 m find the initial velocity he threw it up with

17.15 m/s.

Explanation:

The following data were obtained from the question:

Maximum height (h) = 15 m

Final velocity (v) = 0 m/s

Acceleration due to gravity (g) = –9.8 m/s² (since the ball is going again gravity)

Initial velocity (u) =.?

The initial velocity with which the baseball pitcher threw the ball can be obtained as follow:

v² = u² + 2gh

0² = u² + (2 × –9.8 × 15)

0 = u² + (–294)

0 = u² – 294

Collect like terms

0 + 294 = u²

294 = u²

Take the square root of both side

u = √294

u = 17.15 m/s

Therefore, the baseball pitcher threw the ball with an initial velocity of 17.15 m/s

answer:   you might love summer weather, but you don’t want it to feel like the sun is inside your car. but a hot car that just won’t seem to cool down might be a bigger of a problem than you think. your car relies on being at the right temperature.

explanation:

can be answered using momentum.

momentum = p

p1= mass1 * velocity1

p1 = p2

therefore

p1 = 6kg * 4m/s

p1 = 24kgm/s

p2=m2 * v2

24 kgm/s = 7kg * v2

v2 = 24 kgm/s / 7kg

v2= 3.42 m/s