3. A person who is initially stationary is eventually walking at a speed of 1.5 m/s after an acceleration of 0.5 m/s?,
calculate the distance it takes them to reach this speed.
4. A lorry pulls forward after initially being stationary, it
takes the lorry 40 m to reach a speed of 8 m/s, calculate the
lorry's acceleration.

7. A person begins moving after initially being stationary, the person
accelerates at 0.5m/s2 over a distance of 9m what is their final speed

Explanation:

3. A person who is initially stationary is eventually walking

at a speed of 1.5 m/s after an acceleration of 0.5 m/s?,

calculate the distance it takes them to reach this speed.

Given parameters:

Initial velocity  = 0m/s

Final velocity  = 1.5m/s

Acceleration = 0.5m/s

Unknown:

Distance  = ?

Solution:

To solve this problem, we apply the relevant motion equation;

    V² = U² + 2aS

where V is the final velocity

          U is the initial velocity

          a is the acceleration

         S is the distance

Input the parameters;

     1.5² = 0 + 2 x 0.5 x S

    2.25= S

The distance to reach this speed is 2.25m

4. A lorry pulls forward after initially being stationary, it

takes the lorry 40 m to reach a speed of 8 m/s, calculate the

lorry's acceleration.

Given parameters:

   Initial velocity = 0m/s

   Final velocity  = 8m/s

   Distance  = 40m

Unknown:

Acceleration = ?

Solution:

    V² = U² + 2aS

Input the parameters and solve;

  8² = 0² + 2 x a x 40

   64 = 80a

      a =  = 0.8m/s²

7. A person begins moving after initially being stationary, the person

accelerates at 0.5m/s2 over a distance of 9m what is their final speed

    Given parameters:

    Initial velocity  = 0m/s

    acceleration  = 0.5m/s²

     distance  = 9m

Unknown:

Final velocity  = ?

Solution:

     V² = U² + 2aS

Input the parameters and solve;

   V² = 0² + 3 x 0.5 x 9

    V² = 13.5

    V  = 3.7m/s

an electric circuit