A ball released from rest on an elevated ramp uniformly accelerates at a rate of 3.5 m/s2 for 0.52 s. What is the final speed of the ball?

1.82 m/s

Explaintion:

Use v=u+at

v=0+(3.5×0.52)

v=1.82m/s

v= final speed measured in metres per second

(m/s or ms-¹)

u=Initial speed measured in (m/s or ms-¹)

a=acceleration measured in metres per second squared(ms-²)

t=time measured in second (s)

current flows in a wire

increase masses, decrease separation