A loaded Costco shopping cart has a weight of 188 pounds(lb). You have to push the cart with a force of 14 pounds(lb) to keep it moving with a constant velocity of 1.1 m/s. What must be the magnitude (absolute value) of the force of friction on the cart?

Frictional force along the direction of motion = 14 pounds

Frictional force is  the resistance force towards relative motion. Frictional Force is a force the equation for which is given by the equation

Weight of the  Castco shopping  cart = 188 Pounds (lb)

Force required to push the cart = 14 Pounds

Uniform velocity of shopping cart = 1.1 m/s

Acceleration in the direction of motion of cart = 0 m/s

So we can say that the forces in direction of motion must be balanced

So the  magnitude (absolute value) of the frictional force along the direction of motion

= 14 pounds

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Force of friction = 14 pound

Explanation:

Magnitude = Force / Weight

Magnitude = 14 / 188

Magnitude = 0.074

So,

Force of friction = 14 pound

Force of friction is same as forcee

we're given that v₀ = 0 and a = 5.4 m/s². therefore, since v = at + v₀ for constant acceleration the equation for velocity is

after 28s,

m/s

which i would round to 150 m/s as my final answer

when jerome paddle in flowing river towards east the net speed of jerome will increase

so the net speed of jerome will be given as

now the speed of paul will be same as it is given as he is running on the ground

so

so here we can say since the speed of jerome is more so he will win the race

now as we know the distance so the time difference is given as

so jerome will reach first and the time difference will be 203.55 s or 3.4 min