Note that the origin of the axes is at the legs of the snowboarder for time t = 0. The plot for the “Legs” has been marked up to t = 0. You need to complete the Legs plot across the screen from point t = 0 onward. To do so, mark the Legs position on every frame by holding down the Shift key and clicking the mouse (crosshair cursor) as the video automatically steps through the video clip. See how to plot points. Hint: Zoom your browser display to at least 125% for this marking step, to get the best accuracy in marking the center of the “marker patch” on each frame. After you’ve plotted the rest of the points for the legs, return your browser’s “zoom” setting to 100%. Now look at the graphs for the horizontal and vertical displacement of the legs against time. How do the two graphs, x vs. t and y vs. t appear? What can you say about the displacement of the snowboarder?

10 is the . . .

    m₁v₁ + m₂v₂ = (m₁ + m₂)vmomentum is conserved.the left-hand side of the equation represents the momentum in the system before the collision.the right-hand side represents the momentum in the system after the collisionm₁ and v₁ represents the mass and the velocity of the physics blockm₂ and v₂ represents the mass and velocity of the ball of puttyv represents the final velocity of the combined mass.the question states the two masses stick together. they combined mass has its own velocity with the body mass the sum of the two objects' massestheir combined momentum is (m₁ + m₂)vto find the magitude of (m₁ + m₂)v, we need to add the vectors on the left-hand side of the equation: m₁v₁ + m₂v₂.note the diagram. i have positioned the vectors in accordance with their directions.the magnitude of the resultant can be calculated using the pythagorean theorem since this is a right triangle situation (north and west are perpendicular)|(m₁ + m₂)v| =  √[ (m₁v₁)² + (m₂v₂)² ]|(m₁ + m₂)v| =  √[ (1.5kg·8.0m/s)² + (0.40kg·20m/s)² ]|(m₁ + m₂)v| =  14.4 kg m/sfor two significant figures (assuming that 20m/s is two), this rounds to 14 kg m/s