Billy Sue is speeding down a country road in his new monster truck at a constant 32 m/s when he goes over a hill and spots a cow standing in the middle of the road. The cow is 45m in front of him. If he reacts immediately upon viewing the cow, and his braking acceleration is 20 m/s 2 , can he stop in time to avoid hitting the cow?

He won't stop on time, the distance his car traveled during the braking is greater than 45 m.

Explanation:

Given;

initial velocity of Billy's car, u = 32 m/s

his braking acceleration, -a = 20 m/s

his final velocity when the car stops, v = 0

Apply the following kinematic equation to determine the distance traveled by Billy's car during the braking acceleration;

v² = u² + 2as

0 = 32² + (2 x -9.8)s

0 = 32² - 19.6s

19.6s = 32²

s = (32²) / (19.6)

s = 52.25 m

The distance traveled is greater than 45 m, thus Billy's car will hit the cow.

the answer is 46 mls because when you add the speed per second it increses the speed

current and voltage can both be different in different parts of a circuit so it matters where you place the ammeter and voltmete